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I have given $$ T(n)= \begin{cases} T(n/3)+T(2n/3)+n,\quad &n>1 \\ 1, \quad &n=1 \end{cases} $$ I tried it again and again but couldn't think beyond, $$ T(n)=T(n/27)+3T(2n/27)+3T(4n/27)+T(8n/27) \\ +n/3+2n/3+n/9+8n/9+n $$ What would be next step, if I write $27$ as $3^3$ or $3^k$?

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  • $\begingroup$ There is a "c" in your original equation that is not in your final equation. What happened to it? $\endgroup$ – user247327 Mar 4 at 13:00
  • $\begingroup$ What happens when n is not a whole number? $\endgroup$ – mathpadawan Apr 15 at 16:47

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