# The significance of Abel's Theorem

On p.415 of Bartle's The Elements of Real Analysis, Abel's Theorem is stated as follows:

28.20 ABEL'S THEOREM. Suppose that the power series $$\sum_{n=0}^\infty(a_nx^n)$$ converges to $$f(x)$$ for $$|x|<1$$ and that $$\sum_{n=0}^\infty(a_n)$$ converges to $$A$$. Then the power series converges uniformly in $$I=[0,1]$$ and $$\lim_{x\to1-}f(x)=A.$$

On next page, Bartle wrote (emphasis mine):

One of the most interesting things about this result is that it suggest (sic.) a method of attaching a limit to series which may not be convergent. Thus, if $$\sum_{n=1}^\infty(b_n)$$ is an infinite series, we can form the corresponding power series $$\sum_{n=1}^\infty(b_nx^n)$$. If the $$b_n$$ do not increase too rapidly, this power series converges to a function $$B(x)$$ for $$|x|<1$$. If $$B(x)\to\beta$$ as $$x\to1-$$, we say that the series $$\sum(b_n)$$ is Abel summable to $$\beta$$.... The content of Abel's Theorem 28.20... asserts that if a series is already convergent, then it is Abel summable to the same limit.

Since both $$\sum_{n=1}^\infty(a_nx^n)$$ (with $$|x|<1$$) and $$\sum_{n=1}^\infty(a_n)$$ are assumed to be convergent in the theorem, can somebody please explain what is "series which may not be convergent" in Bartle's discussion?

• He's talking about some other, non-convergent series. Mar 3, 2019 at 15:55
• @SangchulLee That makes sense. Would you please convert your comment into an answer and let me accept it? Mar 3, 2019 at 16:40
• No problem, and glad it helped :) Mar 3, 2019 at 16:45

## 1 Answer

(Migrated from comment)

He is simply telling that the theorem provides an inspiration for defining new type of infinite summation, called Abel summation. It is defined as

$${}^{\mathfrak{A}}\sum_{n=0}^{\infty} a_n := \lim_{x \uparrow 1} \sum_{n=0}^{\infty} a_n x^n$$

(although the notation varies from literature to literature), and in such case, Abel's theorem asserts that 'Abel summability generalizes ordinary summability'. But this also assigns value to series which is not convergent in ordinary summbability, such as

$${}^{\mathfrak{A}}\sum_{n=0}^{\infty}(-1)^n = \frac{1}{2}, \qquad {}^{\mathfrak{A}}\sum_{n=0}^{\infty}(-1)^n n^2 = 0, \qquad \text{etc.}$$