Value of $(a=1) \wedge (b=1) \wedge (c=2)$ given $a=1$, $b=2$ and $c=2$ How would I solve the following question. 
Assume $a=1$, $b=2$ and $c=2$ what is the value of the following Boolean expression
$(a=1)$ AND $(b=1)$ AND $(c=2)$
I am kind of confused because I know the first and is false AND so is the second AND,  so would two false make a true?
 A: No, the statement does not become true because it claims two false things.
A: No, false and true is false, thus the expression evaluates to false.  In the case of ANDs, you can short-circuit on a false since false and anything is always going to be false, just like a true in an OR with anything will evaluate to true.
Truth tables may be useful if you want a reference here.
A: Assume $a=1$, $b=2$, and $c=2.$ 
For the following expression to be true, every statement connected by AND must be true:
$(a=1) \;\; AND \;\; (b=1)\;\; AND\;\; (c=2)\tag{1}$
$(1)$ is true If and ONLY IF EACH of the following are true. 


*

*$a = 1\quad \checkmark\;$ true 

*$b = 1 \quad \color{red}{\bf X}\;\;$ (we are given that $b = 2$, so $b = 1$ is false)

*$c = 2 \quad \checkmark\;$ true


So we have $\qquad{\bf T}\;\;\; AND \;\;\;\color{red}{\bf F} \;\;\;AND \;\;\;{\bf T}\; = \;\; \color{red}{\bf FALSE}$
A: $$(a = 1) \wedge (b = 1) \wedge (c = 2)$$
$$(1 = 1) \wedge (2 = 1) \wedge (2 = 2)$$
$$\text{True} \wedge \text{False} \wedge \text{True} $$
Which is false.
If I say I'm going to get pizza and coke, am I lying if I get neither pizza or coke (yes)? Am I lying if I get both (No)? Am I lying if I get one but not the other (Yes)?
A: $(a=1)$ is TRUE
$(b=1)$ is FALSE (since $b=2$),
therefore result is FALSE
