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I don't really know where to post this but, I think I found an erratum in John Fraleigh's book: "A First Course in Abstract Algebra". On page 29, Definition 3.7, Fraleigh defines an isomorphism in such terms:

Let $\langle S, \star \rangle$ and $\langle S^{'}, \star^{'} \rangle$ be binary algebraic structures. An isomorphism of $S$ with $S^{'}$ is a one-to-one function $\phi$ mapping $S$ onto $S^{'}$ such that: $\phi(x \star y) = \phi(y) \star^{'} \phi(y)$ for all $x, y \in S$

Now, I've looked here at the list of errata for the 7th edition and while there is one on page 29, it doesn't relate to the definition. However, surely the definition is meant to say $\phi(x) \star^{'} \phi(y)$ instead of $\phi(y) \star^{'} \phi(y)$ right?

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    $\begingroup$ Yep, it's a definite typo. Also note that there is a second unofficial errata sheet. $\endgroup$ Commented Mar 2, 2019 at 21:01
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    $\begingroup$ Yes, I think so (b.t.w. errata is a plural – singular is erratum). $\endgroup$
    – Bernard
    Commented Mar 2, 2019 at 21:02
  • $\begingroup$ Cool thanks! Funny how this one is also not present on the unofficial one. I would have presumed that definition, being a very important part of mathematics, would be check twice. $\endgroup$
    – DatCorno
    Commented Mar 2, 2019 at 21:02
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    $\begingroup$ @DatCorno Typos are hard to avoid sometimes. And you have a typo yourself:"would be check twice". $\endgroup$ Commented Mar 2, 2019 at 21:21
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    $\begingroup$ I'm voting to close this question as off-topic because it's an obvious typo so adds no value to the site. $\endgroup$ Commented Mar 3, 2019 at 21:05

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Does anyone know of an errata sheet for the 8th edition? On page 53, in the section on subgroups, Theorem 5.15 reads: "A nonempty subset $H$ of the group $G$ is a subgroup of $G$ if and only if for all $a,b \in G$, $ab^{-1}\in G$", but I think this should read "A nonempty subset $H$ of the group $G$ is a subgroup of $G$ if and only if for all $a,b \in H$, $ab^{-1}\in H$", as this was problem 45 in the 7th edition.

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  • $\begingroup$ Hi Joshua, this is certainly a fair question, but this really is a comment, not an answer, and so it should go in the comments section. Just book-keeping $\endgroup$
    – Mike
    Commented May 27, 2022 at 18:30
  • $\begingroup$ When writing answers, make sure that you do not ask more questions. If you want to ask a question, put it in the comments section. $\endgroup$
    – MathGeek
    Commented May 27, 2022 at 18:35

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