Diffeomorphism and homeomorphism between open ball and polydisc in $\mathbb{R}^n$ Recently I came to know that for $n\geq 2$, the open ball $B(0,1) = \{z\in \mathbb{C}^n: |z|<1\}$ and the polydisc $\Delta(0;1) = \{z\in \mathbb{C}^n: |z_j|<1, j=1,\ldots, n\}$ are not biholomorphic.
This made me wonder whether $B(0,1) = \{x\in \mathbb{R}^n: ||x||<1\}$ and the polydisc $\Delta(0;1) = \{x\in \mathbb{R}^n: |x_j|<1, j=1,\ldots, n\}$ are diffeomorphic?
I know that the product topology on $\mathbb{R}^n$ is equivalent to the metric topology, i.e. topology generated by open polydiscs is same as the one generated by open balls. Does this imply that $B(0,1)$ is homeomorphic to $\Delta(0;1)$?
 A: 
I know that the product topology on $\mathbb{R}^n$ is equivalent to the metric topology, i.e. topology generated by open polydiscs is same as the one generated by open balls. Does this imply that $B(0,1)$ is homeomorphic to $\Delta(0;1)$?

Not if it's for a topological reason. For example, the topology on $\mathbb R^n$ is also generated by the sets which are unions of two open balls of radius $r$ and whose centers are at distance $5r$. But a disjoint union $B(0, 1) \sqcup B(0, 1)$ is definitely not homeomorphic to $B(0, 1)$.


*

*We have a smooth map
$$\begin{align*}
B(0, 1) & \to \mathbb R^n \\
x & \mapsto \frac{x}{\sqrt{1- \|x\|^2}}
\end{align*}$$
with smooth inverse
$$\begin{align*}
\mathbb R^n & \to B(0, 1) \\
y & \mapsto \frac{y}{\sqrt{1 + \|y\|^2}}
\end{align*}$$

*If $g : (-1, 1) \to \mathbb R$ is any diffeomorphism, then
$$\begin{align*}
\Delta(0, 1) & \to \mathbb R^n \\
(x_1, \ldots, x_n) & \mapsto (g(x_1), \ldots, g(x_n))
\end{align*}$$
is a smooth map with smooth inverse
$$\begin{align*}
\mathbb R^n & \to \Delta(0, 1) \\
(y_1, \ldots, y_n) & \mapsto (g^{-1}(y_1), \ldots, g^{-1}(y_n))
\end{align*}$$
A: They are diffeomorphic since they are both open star shaped sets, see  A star shaped open set in $\mathbb{R}^n$ is diffeomorphic to $\mathbb{R}^n$
A: You can indeed show that two balls for two (equivalent) norms are homeomorphic :
Homeomorphism between open unit balls from equivalent distances
