# How to solve this problem raven matrices problem?

I am doing this free test in http://test.mensa.no/

That, as far as I know, the only problem I can't solve.

Basically we shift the first row to the right. From first to second is easy transformation. We just turn the left and right side of the shape outward.

But then from the $$2$$nd row to $$3$$rd, I have no idea what the transformation should be.

What should it be?

• I'm not sure if this has anything to do with matrices, at least in the proper sense of the word in mathematics. – Matti P. Feb 20 at 11:29
• @MattiP. It doesn't. It's "Raven's Matrices" which is not math-related. In fact, this question is probably not considered on-topic. – Eff Feb 20 at 11:37
• Transformation? Mirroring? What? Not Math? – user4951 Feb 20 at 11:37
• Perhaps from 2nd to 3rd row one operation happens to one side of the figure. Only the last figure is possible with one operation on one half of the figure above it. – Paul Feb 20 at 11:54

I think the solution is the picture in the first row last shape.

As you see from first to second row you split the image in the middle and as you put it "turn it outwards" I would say mirroring it around its vertical middle axis. And from second to third row you take the right half of the picture mirror it again first by the vertical middle axis and then the horizontal middle axis.

Hope this helps :)

• Not that easy fella. +1 for effort. But you're wrong. Your transformation would work for the 2nd column but not on the first. – user4951 Feb 20 at 11:37
• Hmm. I still hold my argument. :) – Vinyl_cape_jawa Feb 20 at 11:38
• So we only "work" on the right side? In the first column the left side is the one that switch – user4951 Feb 20 at 12:00
• Hmm. that is true, thank you for pointing it out. Let me rethink this and edit the answer – Vinyl_cape_jawa Feb 20 at 12:10
• You don't think my comment above did the job? – Paul Feb 20 at 13:04