# Does Eigenvalue decomposition (EVD) of a matrix $\mathbf{A}$ mean $\mathbf{Q}$ in wiki,if $\mathbf{A}$ ignore the rank-1 constraint

In this paper ( https://liu.diva-portal.org/smash/get/diva2:1245887/FULLTEXT01.pdf ) the author told me two things

1.$$\mathbf F_k= \mathbf f_k \mathbf f^H_k, \mathbf f_k$$ is a $$N$$ by $$1$$ matrix,and $$\mathbf F_k$$ is a $$N$$ by $$N$$ matrix

2.If we ignore the rank-1 constraint for each $$\mathbf F_k$$,we can obtain $$\mathbf f_k$$ by using Eigenvalue Decomposition (EVD) of $$\mathbf F_k$$.

And i found some information from WIKI,the Eigendecomposition of $$\mathbf A$$ can be written as $$\mathbf{A}=\mathbf{Q}\mathbf{\Lambda}\mathbf{Q}^{-1}$$,so i want to ask,Is $$\mathbf f_k$$ corresponding to the $$\mathbf{Q}$$ in the WiKi?