Is it possible to know the result of a match between three teams with only knowing their goals for and goals against? I've found this problem in my book and left clueless on how to make the right interpretation to come up with a solution. The situation involves a hockey match. Typically when you have a goals for and goals against table you already know the results of the match. But what is the recommended procedure when you don't?.
The problem is as follows:

A tv reporter covering the results of a hockey match group stages for
  the Summer Universiade in Taipei forgot to write down the results of each
  match. There were three teams involved, Netherlands, France and
  Norway. Before airing her segment on the news, she remembered to have
  a handwritten notes of the goals for and goals against between the
  teams mentioned. This table is shown in the diagram from below. The
  reporter tells the viewers that the three teams have played only once
  against each other and each team has played only two matches. If the
  only available footage shown on tv tells the match between France and
  Norway ended in a draw. What was the result of the match between
  Netherlands and Norway?.


The alternatives given were as follows:
$\begin{array}{ll}
1.&3-1\\
2.&2-1\\
3.&3-2\\
4.&1-3\\
5.&4-3\\
\end{array}$
In this particular situation I don't know where to begin. As I mentioned in the opening statement of this question. My doubt arises from the fact that the results from each match is not known and only the one which is known is the one between France and Norway. Does it exist a way to uncover or unhide this from what is known?. I tried to make an equation, but then I figured out. What can I label $x$ ?. 
Upon examination what I could come up with was to know that the only existing combinations between these three are:
Netherland - France
Netherland - Norway
France - Norway
From the goals for it is only known that each team did scored that amount of goals across the entire phase (I suppose that). So at this moment it is not known what exactly the match ended for each team.
I assumed:
For the goals scored in the match:
$\textrm{Netherlands - France = x}$
$\textrm{Netherlands - Norway = y}$
$x+y = 5$
For the goals received in the match:
$\textrm{Netherlands - France = a}$
$\textrm{Netherlands - Norway = b}$
$a+b = 5$
But at this point I got confused on how to use previous information. I suspect that the goals one received accounts for what other has made. But I don't know how to put this piece together with the fact of the draw between the teams as given in the clue from the problem.
Can somebody help me in the right direction for this problem?. I think an answer which would help me the most would be one which can be very detailed in step by step to put the pieces together. Not just solving the problem but more like teaching what should be found first and build that from there. Overall can somebody help me to find an answer for this problem the most easiest way possible?.
 A: This is a very nice question.
Let's start with the known fact that France vs Norway ended in a draw. And let's say that draw is of a score of $a : a$.
Then we know the Netherlands vs France game's result must be: $6-a : 7-a$ since the total goal for France is 7 and goal against is 6.
Similarly, we get that Netherlands vs Norway ended in $5-a:4-a$.
Lastly, we know the goals for Netherlands is $5 = 5 - a + 6 - a$. Therefore, $a=3$ and you can solve for the score of Netherlands vs Norway $2:1$.
A: Here's a somewhat different approach, without algebraic equations.
We see that France and Norway together scored $7+411$ goals. All these goals were either in the France-Norway game, or they were scored against the Netherlands.  Since we know $5$ were scored against the Netherlands, we see $6$ were scored in the France-Norway game, which must have ended in a $3-3$ tie.  
France scored $7$ goals, and $3$ of them were scored against Norway; the other $4$ were scored against the Netherlands. Similarly, $6$ goals were scored against France, $3$ by Norway, so the Netherlands scored the other $3$.  In the same way, we can $subtract$ $3$ from each of Norway's for and against totals to figure out the score in the Norway-Netherlands game.  
France beat the Netherlands $4-3,$ and Norway lost to the Netherlands $1-2.$
The crux of this problem is that each team played only two games, so once you know the score in one of its games, you can figure out the score in the other.
A: Let $Ab$ represent the number of goals made by $A$ against team $b$ and use the abbreviations $L,F,W$ to refer to Netherlands, France, and Norway respectively.  So $Lf$ is the number of goals scored by Netherlands against France for example.
We are told from the table the following information:
$$\begin{cases} Lf+Lw = 5\\Fl+Wl = 5\\ Fl+Fw = 7\\Lf+Wf = 6\\Wf+Wl = 4\\Fw + Lw = 5\end{cases}$$
We are also told one additional piece of information.  The match between France and Norway ended in a draw, giving us the equation:
$$Fw -Wf= 0$$
Including this last equation, this is a linear system of seven equations with six unknowns.  We may then apply Gaussian Elimination to find the solution(s) if any exist.
Letting the columns be in the order $Lf, Lw, Fl, Fw, Wf, Wl$ we have the augmented matrix:
$$\left[\begin{array}{cccccc|c}1&1&0&0&0&0&5\\0&0&1&0&0&1&5\\0&0&1&1&0&0&7\\1&0&0&0&1&0&6\\0&0&0&0&1&1&4\\0&1&0&1&0&0&5\\0&0&0&1&-1&0&0\end{array}\right]$$
After row reducing this leaves us with the augmented matrix:
$$\left[\begin{array}{cccccc|c}1&0&0&0&0&0&3\\0&1&0&0&0&0&2\\0&0&1&0&0&0&4\\0&0&0&1&0&0&3\\0&0&0&0&1&0&3\\0&0&0&0&0&1&1\\0&0&0&0&0&0&0\end{array}\right]$$
From this, we can read out the values for each of $Lf,Lw,\cdots$ and we learn that the result of the match between Netherlands and Norway was $2$-$1$
