I'm stumped on determining P(ABC) of Part A. My understanding is:
Calculate the total number of patients (100)
Calculate individual $P(A), P(B),$ and $P(C)$ $(0.4; 0.35; 0.24 $ respectively)
Multiply $P(A)P(B)P(C) = ANS (0.0336)$
This answer should be the same as $8/20$ or the population of serious patients, under 40, whose parents had diabetes but this fraction comes out to 0.08--what am I missing here? I appreciate your help.