When a polynomial $P(x)$ is divided by $x^2 - 3x$, the quotient and remainder are $Q(x)$ and $2x-8$ respectively. The remainder of division of $Q(x)$ by $x-4$ is $2$. Evaluate the remainder of division of $P(x)$ by $x^2 - 4x$.
From linear division of polynomials, one can conclude that
$$Q(4) = 2$$
I also obtained that
$$P(3) = Q(x)(2x-8)$$
This is where I'm stuck. Could you assist me?