0
$\begingroup$

so I have a question concerning the continuous wavelet transform (please forgive me if this is something very simple however i couldn't seem to find any answer so far):

We know that for the Fourier transform $\mathcal{F}$, under appropriate assumptions on a function $f$, it follows that derivation is equal to multiplication in the sense:

$\mathcal{F}(\frac{d}{dx}f) \propto ix\mathcal{F}(f)$ What I was asking myself now is if there exist wavelets for which something similar holds using the continuous wavelet transform.

Any help would be much appreciated.

$\endgroup$
  • $\begingroup$ Most of the properties of the Fourier transform come from the fact that the $e^{i 2\pi f t}$ functions are the eigen functions of the delay operators. It must be the case for the derivative formula. Then, I have some doubt that you can get the same property exactly with another basis $\endgroup$ – Damien Jan 30 at 9:41
  • $\begingroup$ thank you for your comment. Yes I also realised yesterday that it should only hold for the Fourier transform. However what I found is that when choosing Hermitian Wavelets it at least is again a transform with an hermitian wavelet - up to some constants. Maybe the same holds for other wavelet families ?? $\endgroup$ – RZA Chris Jan 31 at 11:32

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.