# Finding sum to infinity: $\sum\limits_{n = 1}^{ \infty}\frac{n^2}{n!}$ [duplicate]

I am trying to find what this value will converge to $$\sum_{n = 1}^{ \infty}\frac{n^2}{n!}$$
I tried using the Taylor series for $$e^x$$ but couldn’t figure out how to manipulate it to get the above expression, can someone help me out.
This question was merged with What's the value of $\sum\limits_{k=1}^{\infty}\frac{k^2}{k!}$? because it is an exact duplicate of that question.