Suppose I have these numbers:
When I arrange them to find permutations I will get:
$01111$ $10111$ $11011$ $11101$ $11110$
Is this is the idea what is commonly known as "Permutations with repetition"?
If so, then I am not getting the excepted answer: e.g. n! = 5! = 120 permutations.
$$n!/(n-r)! = 120/(5-5)! = 120$$
I am not getting an excepted answer. Is this case something different? Is there a formula?
Is what I am trying to do known as "combinations with repetition"?