# log or ln notation question. [duplicate]

GM,

is log(e) another way of writing ln ? as $$log_{(e)} = ln$$

and consequently when x=1 $$log_{(e)}(1+1/2x) = ln(1+1/2x) = ln(3/2) =0.405$$

Please let me know.

Thank you.

• So you did not see any thing wrong with above statements ? That means log(e) is ln right ? – tt z Jan 14 '19 at 16:28
• $\log_e$ is the same as $\ln$. There's no need for brackets round the $e$. – timtfj Jan 14 '19 at 17:45
• I don't think this is a duplicate of the linked question—this question is specifically about equivalence of notation, and the other question is more about the difference between logs to base $10$ and $e$. Its answers focus mainly on differences between the two functions. – timtfj Jan 14 '19 at 17:51