5
$\begingroup$

I have following question about the Hamiltonian mechanics from differential geometrical viewpoint:

We start with a physical system parametrized by generalized (position) coordinates $(q^i)$ providing under given restrictions the configuration space $Q$ or more precisely a (smooth) manifold.

The tangent bundle $TQ$ over $Q$ provides for the fixed coordinates $q^i$ the corresponding velocities $\dot q ^j$. Geometrically the velocities $\dot q ^j$ at $q^i$ belong to the tangent space $TQ_{q_0}$ at fixed point $q_0^i$ of $Q$.

So $q^i$ and $\dot q ^j$ provide parameters for the Lagrangian $L[q(t), \dot q(t)]$, a function on $TQ$.

On the other hand it's known that the Hamiltionian $H[q(t), p(t)]$ can be interpreted as a function on the cotangent bundle $T^*Q$ where for fixed $q_0^i \in Q$ the momenta $(p_0)_j$ are living in cotangent space $T^*Q_{q_0}$.

My question is why (mathematically) the phase space spanned by position $q^i$ and momentum coordinates $p_j$ come from the cotangent bundle $T^*Q$ while the position $q^i$ and velocity coordinates $\dot q_j$ come from tangent bundle ?

Or in other words why the cotangent space $T^*Q_{q}$ corresponds to momenta while the tangent space $TQ_{q}$ to velocities from viewpoint of differential geometry?

Remark: I know that elemenary physical approach always associates the velocity to the tangent space of the position but this doesn't answer concretely why the momenta spaces should belong exactly to the cotangents.

Intuitively I guess that the velocities and momenta should behave differently under transformations in sense of co- and contravariant coordinates but I'm not sure if this is the real reason for the problem above...

$\endgroup$
  • $\begingroup$ Perhaps this answer could be helpful for you. $\endgroup$ – hypernova Jan 10 at 3:16
1
$\begingroup$

Let $T(q, \dot q)$ denote the kinetic energy of the system at configuration $q$ and velocity $\dot q$. On the tangent plane of some fixed point $q_0$, the kinetic energy induces a norm $\frac{1}{2}\|\dot q\|^2 = T(q_0, \dot q)$ on tangent vectors, which can be extended to an inner product via the polarization identity, and from there to a kinetic energy metric $g_T$ on the entire tangent bundle $TQ$. In this way kinetic energy gives $Q$ its geometric structure.

Momenta live on the cotangent space because they are dual to velocities, in the sense of the musical isomorphisms: a configurational velocity $\dot q$ and its corresponding momentum $p = \dot q^{\flat}$ satisfy, for any other tangent vector $v$, $$pv = \langle \dot q, v\rangle_{g_T}$$ and in particular, $p\dot q = 2T(q,\dot q).$

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.