Circle whose radius is infinite I have the intuition that a circle whose radius is infinite is a straight line.
Nonetheless, I don’t feel that what I’ve just stated  is really scientific as it has some vagueness and lacks precision.
What I  would faithfully ask for is a more accurate expression of this idea ,if it were true, in addition to a proof thereof. 
I would appreciate it if I were provided ,besides your own answers, with some sources to refer to.
Many thanks for considering my request.
 A: A "circle", by definition, has finite radius.  One can say that the limit of a sequence of circles, all passing through two given points, is the straight line passing through those two points.
A: The answer you are looking for kind of depends, as your question is not truely well-defined.
The answer of @user247327, assuming additionally 2 given points and describing a limiting process, which focusses on those provided points, might serve as one possibility.
But there are answers too, which do focus onto the circle center instead.
Eg. one such answer you'd get, when considering circles around the origin with increasing radii within the real projective plane. Then too you'd get the "line of infinity" as the according limit.
A different answer would be obtained, when considering the one-point compactification of $\mathbb{C}=\mathbb{R}^2$. There circles around the origin with ever increasing radii finally result in that additional single point of infinity only. That one then is nothing but the opposite point to the origin on the Riemann sphere.
(For according references just google after the provided terms.)
--- rk
A: Suppose you take a straight line $L$ and fix a point $P \in L$. Consider a variable point $C \in L$, and consider the circle with center $C$ and radius $CP$. This circle crosses the line at right angles at the point $P$. As $C$ goes to infinity in one direction along the line, what can happen? Is there some limiting shape to this circle as $C$ approaches an infinite end of the line $L$?
If you were doing this in the Euclidean plane, then the answer is given by @user247327, the limiting shape is the straight line through $P$ perpendicular to $L$.
However, I notice that you have the tag hyperbolic-geometry on your question. In the hyperbolic plane, the answer is different: the limit is a horocycle, a curve of constant and nonzero curvature which does not close up to form a circle, but the two endpoints of that horocycle instead converge (in the compactification of the hyperbolic plane with its circle at infinity) to the same ideal endpoint of $L$ that $C$ is approaching. 
