Arcs of a circle Geometry and angles If a central angle of measure $30°$ is subtended by a circular arc of length $6\,\mathrm{m}$, how many meters in length is the radius of the circle?
A. $\frac{π}{36}$
В. $\frac{1}{5}$
С. $π$
D. $\frac{36}{π}$
E. $180$


How do I find out what the radius length of the angle is? The answer is (D) by the way.
 A: Let the circle's circumference be given by $C$, let it's diameter = $d$, it's radius $r$.
The ratio of the arc of the circle to the circumference is equal to the ratio of the $30$ degree angle to the measure of a circle = $360^\circ$:
$$\dfrac{6}{C} = \dfrac{30}{360} = \dfrac{1}{12}\quad \implies \quad C = 6\times 12  \implies C=72$$
Using the formula for circumference of a circle: $C = d\pi = 2\pi r$, and solving for r:
$$C = 72 = 2 \pi r $$ $$\implies r = \dfrac{72}{2\pi} = \dfrac{36}{\pi}$$
A: The full circle has perimeter $\frac{360^\circ}{30^\circ}\cdot 6\,\mathrm m=72\,\mathrm m$. As this must equal $2\pi r$, we find $r=\frac{36}\pi\,\mathrm m$.
A: HINT: The circumference of a circle of radius $r$ is $\pi r$. The $30^\circ$ angle is $\frac{30}{360}=\frac1{12}$ of the total angle at the centre of the circle, so $6$ metres is $\frac1{12}$ of the circumference of the circle. The whole circumference is therefore $6\cdot12=72$ metres, which, as already noted, is $2\pi r$. Therefore $r$ is ... ?
A: Length of the arc is $L_\alpha = \alpha r$, so $r = \frac {L_\alpha}\alpha = \frac 6{\pi/6} = \frac {36}\pi$
A: The way that you can solve this is by using the following formula: 
$$A=\frac{n}{360}\pi{r^2}$$
Hope that helps you out!  I can't figure out how to type in the equation!
