I will appreciate someone to verify my answer for exponential distribution question as I am teaching myself and don't have much confidence.
Let X, the number of years a computer works, be a random variable that follows an exponential distribution with a lambda of 3 years. You just bought a computer, what is the probability that the computer will work in 8 years?
what I have: f(x) = $\lambda \cdot e^{-\lambda \cdot x}$ given: $\lambda = 3, x = 8$ so simply $= 3 \cdot e^{-3 \cdot 8} = 3\cdot e^{-24}$?
sorry if this is too low level question. But I'm a bit confused.