Antiderivative: does it represent any area? I was told that an antiderivative doesn't represent any area, it is just a family of functions, but today I noticed something quite interesting thing: 
If we have $f(x)=2x$, then $F(x)=x^2+C$. The area under $f(x)$ from $0$ to $1$ is $1$, and $F(1)$ is one, the area under $f(x)$ from $0$ to $2$ is $4$, and $F(2)$ is $4$, and so on. 
Then I started to think, that when $C=0$, $F(x)$ is the area under $f(x)$ from $0$ to $x$, and tried some others functions like $f(x)=x^2$, $x^3$, and so on.
Then I decided to try $f(x)=\sin x$, and I failed in my guess. But then noticed, if I take $C=1$ it works! Finally, I noticed that it works in all cases when $F(0)=f(0)=0$.
So antiderivative is not only a bunch of functions but also some area?
How can I visualize it generally? How can I visualize $C$? Can this area be an endless area in both directions?
Now I study the fundamental theorem of calculus, and at first, I imagined $F(b)-F(a)$ as $(\text{area from } -\infty \text{ or } 0 \text{ to } b)-(\text{ area from }-\infty \text{ or } 0 \text{ to } a)$. Is it the right visualization?
I will be very grateful if someone could clarify my guesses. Thanks in advance
Upd: thank you all who helped me to solve my problem, i appreciate it so! 
To one, who faced the same question: there`s a quite similar question, and some of answers are pretty meaningful, for example, this one:
https://math.stackexchange.com/a/2559329/595919


 A: Firstly, you can visualize an anti-derivative as a curve itself, whose derivative yields the function with which you are concerned. This new curve can be translated up and down without affecting the slope, therefore you can visualize C as an ambiguous translation of that curve up and down.
As for your understanding of the Fundamental Theorem of Calculus, I would not interpret it as two areas, but rather as the area between a and b itself, which can be found using your anti-derivative function.
I hope that helps.
A: Let $f\colon \Bbb R\to\Bbb R$ be a function that has an anti-derivative $F$. Let $a<b$ be real numbers, then you can use $F$ to calculate the (oriented) area between the vertical lines $x=a$ and $x=b$ that sits between the $x$-axis and the graph of $f$:



More precisely we have
$$
\color{blue}{\text{blue area}} - \color{orange}{\text{orange area}} = \int_a^b f(x)\,\mathrm dx = F(b) - F(a).
$$
Note that the choice of constant in the anti-derivative doesn't matter here, since it cancels when calculating the difference $F(b)-F(a)$.
Letting $a=0$ and choosing the constant such that $F(0)=0$ you get that $F(a)$ is the area under the curve between $x=0$ and $x=a$, as you figured out.
