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Write $y=\frac{2}{3x-6}$ in the form $y=\frac{k}{x-b}+c$

Supposedly simple, but how do you remove the coefficient of x in the denominator and get c? Thanks in advance.

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  • $\begingroup$ Take a factor of $3$ out of the denominator. $c$ may be zero. $\endgroup$ – George Coote Dec 13 '18 at 11:33
  • $\begingroup$ I still don't quite understand what the end result should be? $\endgroup$ – SolvingTrainee Dec 13 '18 at 11:58
  • $\begingroup$ It is awkwardly phrased. Write $\frac 2 {3x - 6} = \frac 2 {3(x - 2)} = \frac {\frac 2 3} {x - 2}$ then k, b, c = ? $\endgroup$ – George Coote Dec 13 '18 at 12:06

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