trouble with $f'$ I'm having a lot of trouble understanding the core concept of finding $f\,'(a)$ or any number in place of $a$. I do not understand what finding $f\,'$ means to begin with, or how to solve them. If somebody could give any information i would be appreciative. 
 A: It's just the derivative.
f'(a) is the derivative of f(x) at x=a.
So for example if f(x)=$x^2$ then f'(x)=$2x$ and f'(a)=$2a$
A: $f'(x)$ is the derivative of $f$ at $x$.
Other similar meanings are
rate of change
slope
grade (of an incline)
pitch, etc.
You know that slope of a line is the ratio of rise over run.
Well the graph of a function may not be a straight line but we can still find something that plays the same role as slope of a line. 
Here is how, at a point  with $x=a$ on the graph  draw its tangent line. The slope of this line is the derivative of $f$ at $a$. 
A: The easiest way to find the derivative using the definition is by using this limit$$f'(a)=\lim_{x\rightarrow a}\frac{f(x)-f(a)}{x-a}$$, For example if $f(x)=x^2-1$ find the derivative at x=1, using the definition we have $$f'(1)=\lim_{x\rightarrow 1}\frac{f(x)-f(1)}{x-1}=\lim_{x\rightarrow 1}\frac{x^2-1-0}{x-1}$$$$=\lim_{x\rightarrow 1}\frac{(x-1)(x+1)}{x-1}$$$$=\lim_{x\rightarrow 1}x+1=2.$$This is the hardest part. After you learn more about derivatives you will learn some rules which are relatively easier to use than the definition, and things should get easier from there.
