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Simple question

I have $$a\cdot b\cdot c\;mod\;p$$

How do I interpret this? Do i read it as this $$(abc)\;mod\;p$$ or is it $$a\cdot b\cdot (c\;mod\;p)$$

Or do I completely misunderstand modular arithmetic?

Thanks!

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Yes, it's $(a b c) \mod p$. In fact $$ x \mod p =(x)\mod p \text{ for any expression } x $$

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  • $\begingroup$ Oh brilliant explanation by generalising x as any expression $\endgroup$ – Jamal Rahman Dec 10 '18 at 7:30
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You can see this as $a*b*c(mod p)$ or $a(mod\ p) *b(mod\ p)* c(mod\ p)$.

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