# Partial sum of harmonic series and one one function

Suppose that $$A$$ is a set of cardinality, say $$n$$. Let $$H_n = 1+1/2+\dots +1/n.$$ If $$\phi:A\to \{1,2,\dots,n\}$$ is one-one, then obviously $$\sum_{a\in A}\phi(a)^{-1} = H_n$$ I'm wondering if the converse of the above statement is true, that is, if $$\phi:A\to \{1,2,\dots,n\}$$ is such that $$\sum_{a\in A}\phi(a)^{-1} = H_n,$$ then should $$\phi$$ be necessarily one-one?

It looks to be true at least for small integers say $$n=2,3,4$$. I have feel that this maybe true. However, I couldn't show this in general. Any hint towards its solution is greatly appreciated.

If some $$\frac{1}{k}$$ terms “disappear” in the sum, the same amount of them should be “overlapping” the terms that are present in the sum. We should show that there’s no chance for it to occur. Unfortunately, that is possible:
$$1+\frac{1}{2}+...+\frac{1}{20}=1+ \frac{1}{2}+ \frac{1}{ 3}+ \frac{1}{5}+ \frac{1}{5}+ \frac{1}{6}+ \frac{1}{6}+...+ \frac{1}{9}+ \frac{1}{11}+...+ \frac{1}{14}+ \frac{1}{16}+...+ \frac{1}{20}+ \frac{1}{20}$$
$$\frac{1}{4}+ \frac{1}{10}+ \frac{1}{15}= \frac{1}{5}+ \frac{1}{6}+ \frac{1}{20}$$