# Limit of a bounded sequence multiplied by a sequence with limit $\infty$ [closed]

I know that if the limit of the second sequence is $$0$$ then the limit of the product is $$0$$,but what if the second sequence has the limit $$\infty$$?

## closed as unclear what you're asking by zhw., Gibbs, amWhy, T. Bongers, user10354138Dec 7 at 2:39

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• This needs to be restated. It's unclear what you're asking. – zhw. Dec 6 at 17:34

$$f(x)=x\sin\bigg(\dfrac{1}{x}\bigg).$$