For a time signal $x(t)= \cos^2(2\pi t)$, solve for the Auto-correlation Function.

Basically I have been following a guide on how to compute the auto-correlation function and am getting hung-up on this Trig equation. The steps I have taken so far are

  1. $\cos^2(2\pi t) = (1/2)[1+\cos(4\pi t)]$
  2. the integral I used to solve for the correlation function (1/T) in front of the integral My main question is if this is the correct process, how would I go about solving this integral when the time delay is present in the second cosine?
  • $\begingroup$ I'm not sure what your question is? $\endgroup$ – Mattos Dec 4 '18 at 23:26

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