Let T be a tree with n vertices,where n greater than or equal to 3.Show that there is a vertex V in T with d(V) greater than or equal to 2 such that every vertex adjacent to V ,except possibly for one ,has degree 1.
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1 Answer
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Let $T’$ be a subgraph of $T$ induced by the set of all vertices of $T$ which have degree at least $2$. Since $T$ is connected and $n\ge 3$, $T’$ is non-empty. Since $T’$ is a subgraph of a tree, it is forest, that is a union of mutually disjoint trees. Choose any of these trees and pick as the required vertex $v$ any its leaf, that is a vertex of degree $1$.