0
$\begingroup$

Knowing that $A$ and $B$ are $2$ matrices of $2\times2$ with elements on $\mathbb{R}$, we have to prove that $\det(A^2+B^2)\ge\det(AB-BA)$ I tried calculating it directly and got nothing. Any ideas?

$\endgroup$
  • $\begingroup$ Thanks for the edit. I'm pretty much new to this site and also quite tired right now. $\endgroup$ – Wolfuryo Nov 28 '18 at 20:34
  • $\begingroup$ Answered in the answer provided by user1551 in math.stackexchange.com/questions/756373/… $\endgroup$ – NoChance Nov 28 '18 at 21:19

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.