Given right associative tetration where:
$^{m}n =$ n^(n^(n^…))
And a situation such as:
$^{m}n = y$
$^{q}p = z$
What is a practical way to calculate which of $y$ and $z$ are larger?
I'm particularly looking at the case where:
$(n, m, p, q)$ are $> 1$
$p > n$
$m > q$
To simplify the question further, assume that $(n, m, p, q)$ are positive integers, they could for example be in the range 10 to 100.
Therefore $(y, z)$ are also positive integers.