How to evaluate the following limit? $$ \lim_{n\to \infty} \frac{i}{n}\left(\frac{1+i}{\sqrt{2}}\right)^n $$ Here $i=\sqrt{-1}$.
I got: $$\lim_{n\to \infty} \frac{i}{n}\left(\frac{1+i}{\sqrt{2}}\right)^n = \lim_{n\to \infty} \frac{(i-1)^n}{n(\sqrt{2})^n} $$ I know the lower part goes to infinity but what to do with the upper part? Is that usefull to use squeeze theorem or is there any simplier way?
$\sqrt{blah blah}$
. A limit of a function f(x) from $n \to \infty$ can be written$\lim_{n\to \infty} f(x)$
. Just a few pointers. $\endgroup$ – amWhy Nov 24 '18 at 21:43$f(x) = \frac{"numerator here"}{"denominator here"}$
$\endgroup$ – amWhy Nov 24 '18 at 21:46