I have the next function: $f(x)=x^3-3x^2+4$.
I need to find an inflection point so I had done the following steps:
I found the first derivative: $f'(x)=3x^2-6x$
Then the second one: $f''(x)=6x-6$
Comparative to zero: $6x-6=0$
I checked values before and after the point in the second derivative:
So the point (1,2) is inflection point but when I chaked the graph, there were not any:
Can someone explain why? Thank You.