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Consider the eigenvalue equation for the Laplace-Beltrami operator on a manifold with metric $ds^2=|K|^{-1}[d\chi^2+\sin_K^2\chi(d\theta^2+\sin^2\theta\,d\phi^2)]$, where: $$\sin_K\chi=\left. \begin{cases} \sin(\chi),\, K>0\\ \sinh(\chi),\, K<0 \end{cases} \right. $$ i.e. the Helmholtz equation: $$ (\Delta + k^2)\,Q_k(x) = 0$$ In the case $K\rightarrow 0$, we obtain the Euclidean metric, for which the (generalized) eigenfunctions are just $Q_k(x)=e^{i \langle k, x\rangle}$ (where $\langle u,w\rangle$ denotes the inner product), and have the property that $Q_k(x+y) = Q_k(x)Q_k(y)$.

The question: in the case $K\neq 0$, do the (generalized) eigenfunctions have the above property?

I am aware that in the case $K\rightarrow 0$, we can expand the eigenfunctions in spherical coordinates as spherical harmonics so that $e^{i\langle k, x \rangle} = 4\pi\sum\limits_{\ell,m} i^\ell Y^m_l(\theta,\phi) j_l(k\, r)$, and that in the case $K\neq 0$ only the radial equation is changed, for which the solutions are hyperspherical Bessel functions, however I can't seem to prove the additive property as there's no closed form for the eigenfunctions.

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  • $\begingroup$ Should I have posted this on mathoverflow instead? $\endgroup$ – GreaterThanZero Dec 9 '18 at 16:29

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