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Given that the turning point of this parabola is (-2,-4) and 1 of the roots is (1,0), please find the equation of this parabola. I started off by substituting the given numbers into the turning point form. $0=a(x+2)^2-4$ but i do not know where to put the roots in and form an equation.Please help thank you.

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Guide:

The equation is

$$y=a(x+2)^2-4$$

Now, use the property that it passes through $(1,0)$ to solve for $a$.

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    $\begingroup$ Since the vertex is $(-2, -4)$, the equation should have the form $y = a(x + 2)^2 - 4$. $\endgroup$ – N. F. Taussig Nov 6 '18 at 11:20
  • $\begingroup$ oops, you are right, thanks. $\endgroup$ – Siong Thye Goh Nov 6 '18 at 11:22

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