Set $A$ is given as
$A=\{(x,\frac{1}{x}) : x\geq 1\} \cup \{(0,2)\} \subset \mathbb{R^2}$
Find a closure of a $conv(A)$.
I wanted to find a convex hull first but I am confused what to do with a point $(0,2)$.
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$\begingroup$ please provide a picture $\endgroup$ – LinAlg Nov 4 '18 at 19:18
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Hint: If $B=conv(\{(x,\frac{1}{x}) : x\geq 1\})$, then $conv(A)$ is the union of $B$ with all line segments joining $(0,2)$ to a point of $B$.
