How to find probability of one six when a six-sided die is thrown three times ? I tried out the tree diagram but I couldn't get the answer. Please if anyone can help me to solve this problem.

Thank you


closed as off-topic by John B, user10354138, Henrik, Gibbs, Xander Henderson Nov 4 '18 at 0:06

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – John B, user10354138, Henrik, Gibbs, Xander Henderson
If this question can be reworded to fit the rules in the help center, please edit the question.

  • $\begingroup$ As a hint: since you don't care about the exact value of the non-$6$ outcomes of a single die roll, you can just imagine that there are only two possible outcomes, namely $6$ and $X$ where $X$ just stands for "not $6$". Of course they have different probabilities, namely $\frac 16$ and $ \frac 56$. $\endgroup$ – lulu Nov 3 '18 at 20:36
  • 1
    $\begingroup$ When you say one six, I assume you mean exactly one six. This is a binomial distribution with $p = \frac{1}{6}$ and $q = 1 - p = \frac{5}{6}$. $\endgroup$ – Bob Nov 3 '18 at 20:51

Here is my attempt at a tree. Note, there are $3$ ways to get a single $6$.

enter image description here


Not the answer you're looking for? Browse other questions tagged or ask your own question.