I am trying to solve $2^x = 3^x$ for $x$.
Now I plug this into WolframAlpha and the steps to the solution are the following:
- Take natural log of both sides which leaves me with this (according to them):
$$ x\ln(2)= x\ln(3) + 2in\pi $$
What I don't understand is where is this $2in\pi$ coming from?
Thank you very much for your time and help.