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What is $\ln(e^{ix})$? Why isn't it $ix$?

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    $\begingroup$ because complex logs have branches. Which branch are you working in? $\endgroup$ – gt6989b Oct 29 '18 at 20:25
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    $\begingroup$ The complex logarithm is multivalued and so the possible values are $\log(e^{ix})=i (x+2n\pi)$ for integer values of $n$ $\endgroup$ – Mark Viola Oct 29 '18 at 20:28
  • $\begingroup$ Thank you both. $\endgroup$ – Malcolm Regan Oct 29 '18 at 20:31

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