Solving complicated fraction for X I realize this rather rudimentary but it has been over a decade since my algebra classes and now I have problem that I can't figure out. I would like someone to walk me through the steps in solving the "X" in this problem:
$$
1.20 \cdot 10^6 = \frac{1}{\left(\dfrac{1}{6 \cdot 10^6}\right)  X}
$$
So what I've done so far is this:
$$1,200,000 =  \frac{1}{166,666.67X}$$
$$(166,666.67X) * 1,200,000 =  \frac{1}{166,666.67X} * (166,666.67X)$$
$$200,000,004,000x = 1$$ But this doesn't make sense.
I supposed to get $x = 5$.
Thanks!
EDIT:
The formula is this:
                   1  
MTTF(system) = ---------------
                 n     1
                 E ----------
                i=1   MTTFi

This is my best as I can't upload the image and not sure how else to post this. So the "E" is actually the greek letter for sumation. The "n" would be 1 since this only one system.
MTTF(system) = 1,200,000;
MTTFi = 6,000,000

 A: $$1.20 \cdot 10^6 = \dfrac{1}{\left(\frac{1}{6\cdot10^6}\right)X} \iff 1.2\cdot 10^6 = \frac{6\cdot 10^6}{X}$$
$$\iff X =\frac{6\cdot 10^6}{1.2\cdot 10^6} = \frac {6}{1.2} = 5$$
The nice thing about the problem is that there is no need to evaluate numerically until the very end, where we need only compute $X =\dfrac{6}{1.2}$ (factors of $10^6$ cancel out, in the process)
Another way to think of the problem is as follows (multiplying both sides of the equation by $\dfrac{1}{6\cdot 10^6}$ to cancel out the fraction in the denominator of the right-hand side: $$1.20 \cdot 10^6 = \dfrac{1}{\left(\frac{1}{6\cdot10^6}\right)X} \iff 1.2\cdot 10^6 \cdot \frac{1}{6\cdot 10^6} = \frac{1}{6\cdot 10^6} \cdot \frac{1}{\frac{1}{6\cdot 10^6}X}$$
$$\iff \frac{1.2}{6} = \frac{1}{X} \iff 1.2x = 6\iff X = \frac{6}{1.2} = 5 $$
A: You can make an exact calculation, without resorting to approximations. Multiply both sides by $\dfrac{1}{6} \cdot 10^6$ to get
$$
1 = 1.20 \cdot \dfrac{1}{6} \cdot 10^{12} X = \frac{1}{5} \cdot 10^{12} X.
$$
This gives $X = \dfrac{5}{10^{12}}$. 

Since you expect the solution to be $X = 5$, I suppose there is a misprint in your statement, and one of the $10^6$ is actually a $10^{-6}$.

A: $1.2 \times 10^6 = \displaystyle \frac{1}{ \frac{1}{6} \times 10^6 x}$
$\Rightarrow (1.2 \times 10^6) \times( \frac{1}{6} \times 10^6 x) = 1$
$\Rightarrow (1.2 \times \frac{1}{6}) \times 10^{12} \times x = 1$
$\Rightarrow (\frac{1}{5} \times 10^{12}) \times x = 1$
$\Rightarrow  x = 5 \times 10^{-12}$
