I'm trying to solve the following differential equation with Wolfram Alpha (I have a pro subscription):
y''+2*a*y'+(a^2-c^2-b/d*Exp(-x/d)-b^2*Exp(-2*x/d))*y=0
I want to assume that 'a', 'b', 'c', 'd' and 'x' are real positive numbers. How do I do this in Wolfram|Alpha?
Currently, by not assuming that, I'm getting analytic solutions but it contains associated Laguerre polynomials 'L': $$ y(x)=k_1 U\left(c d+1,2 c d+1,2 b d e^{-x/d}\right) \exp \left(d \left((a+c) \log \left(e^{-x/d}\right)-b e^{-x/d}\right)\right)+k_2 L_{-c d-1}^{2 c d}\left(2 b d e^{-x/d}\right) \exp \left(d \left((a+c) \log \left(e^{-x/d}\right)-b e^{-x/d}\right)\right) $$ where the n=-cd-1 is a not a real number.
Edit: Didn't know but Laguerre polynomials are defined for non-integer orders as well. My question still remains for the syntax of "assuming" in Wolfram Alpha though.