# The volume of a child's model plane is $1200~\rm{cm}^3$ & that of a full size plane is $4050~\rm{m}^3.$ Find the scale of the model in the form $1:n.$

The volume of a child's model plane is $$1200~\mathrm{cm}^3.$$ The volume of a full size plane is $$4050~\mathrm{m}^3.$$ Find the scale of the model in the form $$1:n.$$

I thought of first converting the $$4050~\mathrm{m}^3$$ to $$\mathrm{cm}^3,$$ giving me $$4050000000~\mathrm{cm}^3.$$ Then, I divided the number by $$1200$$: reversing the order of conversion. So, my final answer was $$1: 3375000.$$ However, the answer in the mark scheme is $$150.$$

• 1:3 000 000 is a scale best used in a (small) world atlas. It would fit most of the island of Great Britain into an A4 page. Oct 25, 2018 at 13:19
• @Arthur Maybe children love nanotech models? Oct 25, 2018 at 15:30

Your idea was almost correct, but remember that the scaling will be in terms of length, so you should take the cube root of your answer of 3375000.

• Oh right, thanks a lot!
– V11
Oct 25, 2018 at 13:21
• And just to close the loop, 150 cubed is 3,375,000. Oct 25, 2018 at 16:20
• You say "remember," but is there anything other than convention that dictates that the scale is in terms of length? @user608398, does the original problem say it is by length? Or is this just a convention the person is expected to know? Oct 25, 2018 at 16:40

Say there is a real cube measuring $$1\times 1\times 1$$ meters, and I have a model of it in the scale $$1:2$$. Then my model will measure $$\frac12\times\frac12\times\frac12$$ meters. What is the ratio of volumes between my model cube and the real cube? What if my model was $$1:3$$?

See if you can use these simple examples to figure out the general pattern that links the model scale to the ratio of volumes. Then, from your ratio of volumes, deduce the scale.

Ok, your volume ratio is to be converted to length ratio by taking cuberoot.

Looking at it same way... the scaling is for linear/length dimension. So,

$$n=(4050/1200)^{1/3}=1.5$$

if we ignore the units. To take units into consideration this should be multiplied by scale factor

$$\dfrac{meter}{centimeter}= 100$$

giving $$n=150.$$