Existence and Uniqueness Theorem I had a question about how to do one of these problems. So here's the question:
Given this equation $y'=\frac{-\cos(t)y(t)}{(t+2)(t-1)}+t$, find if the initial conditions $y(0)=10, y(2)=-1, y(-10)=5$ exist.
So I think the first step is just to take the partial derivative with respect to y which gives me:
$$y''=\frac{-\cos(t)y'(t)}{(t+2)(t-1)}$$
So the 1'st equation doesn't exist at $t=-2,1$ and the partial derivative doesn't exist at $t=-2,1$ ....so do I conclude that all the initial values exists since none of them are $y(-2)$ or $y(1)$.
Don't really know how to do this whole existence and uniqueness thing....so am I right or completely off track?  
 A: What you've done looks perfectly fine.
Here's a general outline of what you do when you're looking to find where solutions exist for the first-order differential equation $y'+ p(t) y = g(t)$.

  
*
  
*Write the differential equation in the form: $y'=f(y, t)$
  
*Find $f_y = \frac{\partial}{\partial y} f$.
  
*Determine points of discontinuities of both $f_y$ and $f$.

At this point, if you're just looking to see if a particular initial condition ($t_0$) has a solution, just check if $t_0$ is one of the points of discontinuity.
If you're looking for where the solution exists:

  
*
  
*Draw a number line denoting where the discontinuities are (if possible).
  
*Find where the initial condition falls on the number line.
  
*If the discontinuity to the left of $t_0$ is $a$, and the discontinuity to the right of $t_0$ is $b$, then the solution exists on the interval $(a, b)$.
  

EDIT
Based on requests from comments below, here's a statement of the existence and uniqueness theorem:

Let the functions $f$ and $\frac{\partial f}{\partial y}$ be continuous in some rectangle $\alpha < t < \beta$, $\gamma < y < \delta$ containing the point $(t_0, y_0)$.  Then, in some interval $t_0 - h < t < t_0 + h$ contained in $\alpha < t < \beta$, there is a unique solution $y = \phi(t)$ of the initial value problem:
$$\begin{array}{cc}
y' = f(t,y) & y(t_0) = y_0.
\end{array}$$

Source: Elementary Differential Equations and Boundary Value Problems, Boyce and DiPrima, 10th Edition, pg 70.
