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I'm not sure how to get started with the following. Consider,

$- \Delta u=f$ in $\Omega$

$u=u_o$ on $\Gamma$

I need to find a $u \in V(u_o)$ such that

$a(u,v)=(f,v)$ $\forall v\in H^1_o$ where

$V(u_o)$={$v\in H^1 \Omega$: $v = u_o$ on $\Gamma$}

Now I think that I need to use Green's formula here but the only problem I'm running into now is that I can't say that the boundary integral goes to $0$ because in this case it's $u_o$.

Any help on how to go about this would be insightful!

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  • $\begingroup$ This looks like a problem you have collected from / inspired by some source. According to recent discussions in Meta, we are looking forward to including sources for all applicable questions. Can you provide the source by editing the question?Refer-math.meta.stackexchange.com/questions/29290/… $\endgroup$ – tatan Oct 23 '18 at 6:25
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You need that $V(u_0)$ is non-empty, that is, there is $v_0\in V(u_0)$. Then split the unknown $u=v_0 + u_0$, where $u_0\in H^1_0(\Omega)$ solves $$ a(u_0,v) = (f,v) - a(v_0,v) \quad \forall v\in H^1_0(\Omega). $$ Just superposition principle for linear equations.

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  • $\begingroup$ I was thinking more along the lines of maybe splitting the solution by calling a $u_g=u-u_o$ then have the new problem be, $-\Delta u = f + u_g$ with the new boundary being $u_g=0$. This would then let me try Green's formula by splitting the domain @daw $\endgroup$ – lnbmoco Oct 24 '18 at 17:31

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