If I roll 3 dice with n sides, and then roll a 4th die of the same size, what are the odds of it being higher than at least one of the previous rolls?
I'm thinking it should be something like the odds of rolling a 1 in the first 3 dice times the odds of rolling a 2 or higher on the last die, giving me this equation.
$(1 - ((n-1)/n)^3)*((n-1)/n)$
Is this equation correct? I feel like I'm missing something.