Two shooters A and B are shooting two separately targets, Probabilities of target hitting are 0.3 For A and 0.6 For B. Calculate these probabilities :
A) At least one shooter hits the target:
My answer : P(A) + P(B) - P(A)*P(B) = 0.3 + 0.6 - 0.18 = 0.72
B) Just only one shooter hit the target:
My Answer: P(A-B) + P(B-A) = P(A) + P(B) - 2[P(A)*P(B)] = 0.3 + 0.6 - 2*0.18 = 0.54
C) None of them shootings hit the target:
My Answer : 1 - P(A) + P(B) - P(A)*P(B) = 1 - 0.72 = 0.28
Are my answers correct? Any idea to solve these problems in another ways ?