If a have a system of equation

$$ \frac{d u}{dt} = 1- u e^{\epsilon(q-1)}$$

$$ \frac{d q}{dt} = u e^{\epsilon(q-1)}-q$$

$u(0)=q(0)= 0$

How Can I apply the perturbation methot

$\epsilon$ small parameter

  • 1
    $\begingroup$ Expand the exponentials with a power series. $\endgroup$ – Paul Oct 17 '18 at 20:46
  • $\begingroup$ Ok, but when I solve the equations one by one. Or one equation have relation whit the other. $$u(t)=u_0(t)+\epsilonu_1(t)$$ I know the power series of $e^{\epsilon(q-1)}$ is $1 + \epsilon(q-1)+ 0.5\epsilon^2(q-1)^2$ when I introduce the previous power series in the first equation $$u'_0+u_0-1 +\epsilon (u'_1+u_0(q-1)+u_1)+ \epsilon^2 (u_0(q-1)^2+u_0(q-1)+u_1)+ O(\epsilon^3)=0$$ I can solve this but have some relation whit the other equation? $\endgroup$ – Conan Oct 17 '18 at 21:17
  • $\begingroup$ First introduce the new variable $q-1$. $\endgroup$ – John B Oct 18 '18 at 8:35
  • $\begingroup$ Do the same thing with $q$ (or $q-1$), write $q=q_0+\epsilon q_1+\dots$ and substitute in. $\endgroup$ – David Oct 18 '18 at 17:09

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