What is an example of a compact non-uniformizable space? Every compact Hausdorff space is uniformizable.  But I don’t think every compact space is uniformizable.  So my question is, what is an example of a compact non-uniformizable space?
 A: Recall that the topology on every uniform space is completely regular, and hence regular.
Let $X$ be Sierpinski space, i.e. $X=\{0,1\}$ with the topology $\{\emptyset,X,\{0\}\}$. Then $X$ is trivially compact, but is not regular because $\{1\}$ is closed and doesn't contain $0$, but every open set containing $\{1\}$ also contains $0$. Thus, $X$ is not uniformizable.
A: A topology from a uniform space is $R_0$ (also called symmetric). This means that topologically distinct points can be separated by disjoint open sets, where points $x \neq y$ are topologically indistinguishable iff $\overline{\{x\}} = \overline{\{y\}}$ (or equivalently if for every open set $O$ we have $x \in O$ iff $y \in O$). So e.g. a $T_1$ space that is $R_0$ is also Hausdorff (because then the closures of singletons are singletons, so all points are distinguishable and must be "separatable"). The same holds for $T_0$ spaces (because $T_0$ can be seen as equivalent to "all distinct points of $X$ are topologically distinguishable"). This means that the following are standard examples of compact non-$R_0$ spaces: The cofinite topology on any infinite set, the excluded point topology on any set, as they are $T_0$ and not $T_2$. 
That a topology from a uniformity is $R_0$ is a standard fact (and follows from the fact that every entourage $D$ contains a symmetric entourage $E$, i.e. one where $E = E^{-1}$). 
Any indiscrete space is uniformisable (trivially) and is an example of a compact uniformisable space that is not Hausdorff. 
But if $X$ is uniformisable then $T_0$, $T_1$, $T_2$, $T_3$ and Tychonoff are all equivalent properties (if you have one, you have them all), so in a way, indiscrete is the best you can do as far as non-Hausdorff examples go (finite sums of them, too, if you like)
