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Is there a way to split the following floor function setup into two separate terms with the x in one term and the c in another term? Such as:

$a\left \lfloor{\frac{x+b}{c}}\right \rfloor$ = $a\left \lfloor{\frac{x}{c}}\right \rfloor + f(b)$

Where $f(b)$ is some term not involving x in it that may necessarily have a floor function operator.

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  • $\begingroup$ no, not really. Floor is a weird function. $\endgroup$ – Don Thousand Oct 10 '18 at 1:57

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