# Find the radius of convergence for this power series

So originally I needed to turn the function $$f(x)=\frac{3}{2-x}$$ into a power series. I think I did this successfully and got $$\sum_{n=0}^\infty \frac{3x^{n}}{2^{n+1}}$$ Now I'm struggling to find the radius of convergence. I set up a form of the ratio test to find it: $$\lim_{n\to \infty}|\frac{\frac{3x^{n+1}}{2^{n+2}}}{\frac{3x^{n}}{2^{n+1}}}|$$ and got $$|\frac{x}{2}|$$. I'm not sure what this means in terms of the radius of convergence

Why make things mre comples than they are? You obtained this power series from the factorisation $$\frac3{2-x}=\frac32\,\frac1{1-\cfrac x2},$$ and using the power series expansion of $$\dfrac1{1-u}$$ with $$u=\dfrac x2$$, so the radius of convergence is defined by $$\biggl|\frac x2\biggr|<1\iff |x|<2.$$