Suppose that $B_1$ is the bases for $x^{*}$ and I want to go to the second solution $y^{*}$ with bases $B_2$, how to go to the second optimal solution through pivoting? My attempt was trying to prove that the reduced costs of the variables in bases $B_2$ is zero, but it was unsuccessful.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.