# Area of irregular similar hexagons [closed]

Irregular Hexagons $$A$$ and $$B$$ are geometrically similar. The shortest sides are $$4$$ inches and $$3$$ inches, respectively. If the area of hexagon $$A$$ is $$48in^2$$, what is the area of hexagon $$B$$?

I know the answer is $$27 in^2$$, but how do you get that?

## closed as off-topic by Saad, Leucippus, Xander Henderson, Chris Custer, Ahmad BazziOct 1 '18 at 5:44

This question appears to be off-topic. The users who voted to close gave this specific reason:

• "This question is missing context or other details: Please improve the question by providing additional context, which ideally includes your thoughts on the problem and any attempts you have made to solve it. This information helps others identify where you have difficulties and helps them write answers appropriate to your experience level." – Saad, Leucippus, Xander Henderson, Chris Custer, Ahmad Bazzi
If this question can be reworded to fit the rules in the help center, please edit the question.

Because if corresponding linear dimensions of $$A$$ and $$B$$ are in $$4:3$$ ratio, then their areas are in $$4^2:3^2$$ ratio.
The areas of similar figures vary in proportion to the square of the proportion by which the lengths are stretched. For example, a square with one and one half times the side length has area $$(3/2)^2$$ as large.