0
$\begingroup$

Question:

Solve for $y$. $$\ln y = 3t + 8$$

I tried answering the question with $$(\ln x - 8)/3$$ but I am told it's wrong. I'm really confused with the logarithms unit, so any help would be very appreciated!

$\endgroup$
  • $\begingroup$ If you'd been solving for $t$, you would've been correct! :) (Well, except that you changed the $y$ to an $x$ for some reason.) $\endgroup$ – Blue Sep 29 '18 at 0:25
2
$\begingroup$

There is one single trick with logarithms: isolate a logarithm and exponentiate. In your case $\log y = 3t+8$ the logarithm is already isolated, so we exponentiate: $$ e^{\log y} = e^{3t+8} $$ but $e^{\log y} = y$, so $y = e^{3t+8}$.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.